E=(7x-5)(6x-8)

Solution for E=(7x-5)(6x-8) equation:

=(7E-5)(6E-8)

We move all terms to the left:

-((7E-5)(6E-8))=0

We multiply parentheses ..

-((+42E^2-56E-30E+40))=0


We calculate terms in parentheses: -((+42E^2-56E-30E+40)), so:

(+42E^2-56E-30E+40)

We get rid of parentheses

42E^2-56E-30E+40

We add all the numbers together, and all the variables

42E^2-86E+40

Back to the equation:

-(42E^2-86E+40)


We get rid of parentheses

-42E^2+86E-40=0

a = -42; b = 86; c = -40;
Δ = b2-4ac
Δ = 862-4·(-42)·(-40)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-26}{2*-42}=\frac{-112}{-84}
=1+1/3
$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+26}{2*-42}=\frac{-60}{-84}
=5/7
$