F(-2)=x2+3x-10

Solution for F(-2)=x2+3x-10 equation:

(-2)=F2+3F-10

We move all terms to the left:

(-2)-(F2+3F-10)=0

We add all the numbers together, and all the variables

-(+F^2+3F-10)+(-2)=0

We add all the numbers together, and all the variables

-(+F^2+3F-10)-2=0

We get rid of parentheses

-F^2-3F+10-2=0

We add all the numbers together, and all the variables

-1F^2-3F+8=0

a = -1; b = -3; c = +8;
Δ = b2-4ac
Δ = -32-4·(-1)·8
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{41}}{2*-1}=\frac{3-\sqrt{41}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{41}}{2*-1}=\frac{3+\sqrt{41}}{-2}
$