F(-3)=2x2+2

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Solution for F(-3)=2x2+2 equation: 



(-3)=2F^2+2

We move all terms to the left:

(-3)-(2F^2+2)=0

We add all the numbers together, and all the variables

-(2F^2+2)-3=0

We get rid of parentheses

-2F^2-2-3=0

We add all the numbers together, and all the variables

-2F^2-5=0

a = -2; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-2)·(-5)
Δ = -40
Delta is less than zero, so there is no solution for the equation

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