F(-5)=3(-5)+2,g(-5)=-2(-5)2,

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Solution for F(-5)=3(-5)+2,g(-5)=-2(-5)2, equation: 



(-5)=3(-5)+2.F(-5)=-2(-5)2.

We move all terms to the left:

(-5)-(3(-5)+2.F(-5))=0

We add all the numbers together, and all the variables

-(3(-5)+2.F(-5))-5=0



We calculate terms in parentheses: -(3(-5)+2.F(-5)), so:

3(-5)+2.F(-5)

determiningTheFunctionDomain
2.F(-5)+3(-5)

We add all the numbers together, and all the variables

2.F(-5)-15

We multiply parentheses

-10F-15

Back to the equation:

-(-10F-15)



We get rid of parentheses

10F+15-5=0

We add all the numbers together, and all the variables

10F+10=0

We move all terms containing F to the left, all other terms to the right

10F=-10

F=-10/10

F=-1

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