F(0)=3-(2x+5)

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Solution for F(0)=3-(2x+5) equation: 



(0)=3-(2F+5)

We move all terms to the left:

(0)-(3-(2F+5))=0

We add all the numbers together, and all the variables

-(3-(2F+5))=0



We calculate terms in parentheses: -(3-(2F+5)), so:

3-(2F+5)

determiningTheFunctionDomain
-(2F+5)+3

We get rid of parentheses

-2F-5+3

We add all the numbers together, and all the variables

-2F-2

Back to the equation:

-(-2F-2)



We get rid of parentheses

2F+2=0

We move all terms containing F to the left, all other terms to the right

2F=-2

F=-2/2

F=-1

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