F(1)=2f(0-1)+6

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Solution for F(1)=2f(0-1)+6 equation: 



(1)=2F(0-1)+6

We move all terms to the left:

(1)-(2F(0-1)+6)=0

We add all the numbers together, and all the variables

-(2F(-1)+6)+1=0



We calculate terms in parentheses: -(2F(-1)+6), so:

2F(-1)+6

We multiply parentheses

-2F+6

Back to the equation:

-(-2F+6)



We get rid of parentheses

2F-6+1=0

We add all the numbers together, and all the variables

2F-5=0

We move all terms containing F to the left, all other terms to the right

2F=5

F=5/2

F=2+1/2

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