F(1/2)=2/3x+5

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Solution for F(1/2)=2/3x+5 equation: 



(1/2)=2/3F+5

We move all terms to the left:

(1/2)-(2/3F+5)=0



Domain of the equation: 3F+5)!=0

F∈R



We add all the numbers together, and all the variables

-(2/3F+5)+(+1/2)=0

We get rid of parentheses

-2/3F-5+1/2=0

We calculate fractions

There is no solution for this equation

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