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(10)=1/2F-6
We move all terms to the left:
(10)-(1/2F-6)=0
Domain of the equation: 2F-6)!=0We get rid of parentheses
F∈R
-1/2F+6+10=0
We multiply all the terms by the denominator
6*2F+10*2F-1=0
Wy multiply elements
12F+20F-1=0
We add all the numbers together, and all the variables
32F-1=0
We move all terms containing F to the left, all other terms to the right
32F=1
F=1/32
F=1/32
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