F(100)=9/5x+32

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Solution for F(100)=9/5x+32 equation: 



(100)=9/5F+32

We move all terms to the left:

(100)-(9/5F+32)=0



Domain of the equation: 5F+32)!=0

F∈R



We get rid of parentheses

-9/5F-32+100=0

We multiply all the terms by the denominator


-32*5F+100*5F-9=0

Wy multiply elements

-160F+500F-9=0

We add all the numbers together, and all the variables

340F-9=0

We move all terms containing F to the left, all other terms to the right

340F=9

F=9/340

F=9/340

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