F(120)=3x+12

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Solution for F(120)=3x+12 equation: 



(120)=3F+12

We move all terms to the left:

(120)-(3F+12)=0

We get rid of parentheses

-3F-12+120=0

We add all the numbers together, and all the variables

-3F+108=0

We move all terms containing F to the left, all other terms to the right

-3F=-108

F=-108/-3

F=+36

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