F(2)=3(x+x)-8

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Solution for F(2)=3(x+x)-8 equation: 



(2)=3(F+F)-8

We move all terms to the left:

(2)-(3(F+F)-8)=0

We add all the numbers together, and all the variables

-(3(+2F)-8)+2=0



We calculate terms in parentheses: -(3(+2F)-8), so:

3(+2F)-8

We multiply parentheses

6F-8

Back to the equation:

-(6F-8)



We get rid of parentheses

-6F+8+2=0

We add all the numbers together, and all the variables

-6F+10=0

We move all terms containing F to the left, all other terms to the right

-6F=-10

F=-10/-6

F=1+2/3

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