F(2)=5/3x-4

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Solution for F(2)=5/3x-4 equation: 



(2)=5/3F-4

We move all terms to the left:

(2)-(5/3F-4)=0



Domain of the equation: 3F-4)!=0

F∈R



We get rid of parentheses

-5/3F+4+2=0

We multiply all the terms by the denominator


4*3F+2*3F-5=0

Wy multiply elements

12F+6F-5=0

We add all the numbers together, and all the variables

18F-5=0

We move all terms containing F to the left, all other terms to the right

18F=5

F=5/18

F=5/18

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