F(2-k)=8-5(2-k)

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Solution for F(2-k)=8-5(2-k) equation: 



(2-F)=8-5(2-F)

We move all terms to the left:

(2-F)-(8-5(2-F))=0

We add all the numbers together, and all the variables

(-1F+2)-(8-5(-1F+2))=0

We get rid of parentheses

-1F-(8-5(-1F+2))+2=0



We calculate terms in parentheses: -(8-5(-1F+2)), so:

8-5(-1F+2)

determiningTheFunctionDomain
-5(-1F+2)+8

We multiply parentheses

5F-10+8

We add all the numbers together, and all the variables

5F-2

Back to the equation:

-(5F-2)



We get rid of parentheses

-1F-5F+2+2=0

We add all the numbers together, and all the variables

-6F+4=0

We move all terms containing F to the left, all other terms to the right

-6F=-4

F=-4/-6

F=2/3

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