F(3x-12)=5(3x-12)+4

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Solution for F(3x-12)=5(3x-12)+4 equation: 



(3F-12)=5(3F-12)+4

We move all terms to the left:

(3F-12)-(5(3F-12)+4)=0

We get rid of parentheses

3F-(5(3F-12)+4)-12=0



We calculate terms in parentheses: -(5(3F-12)+4), so:

5(3F-12)+4

We multiply parentheses

15F-60+4

We add all the numbers together, and all the variables

15F-56

Back to the equation:

-(15F-56)



We get rid of parentheses

3F-15F+56-12=0

We add all the numbers together, and all the variables

-12F+44=0

We move all terms containing F to the left, all other terms to the right

-12F=-44

F=-44/-12

F=3+2/3

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