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(4)=1/2F+3
We move all terms to the left:
(4)-(1/2F+3)=0
Domain of the equation: 2F+3)!=0We get rid of parentheses
F∈R
-1/2F-3+4=0
We multiply all the terms by the denominator
-3*2F+4*2F-1=0
Wy multiply elements
-6F+8F-1=0
We add all the numbers together, and all the variables
2F-1=0
We move all terms containing F to the left, all other terms to the right
2F=1
F=1/2
F=1/2
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