F(4)=2/5x+11

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Solution for F(4)=2/5x+11 equation: 



(4)=2/5F+11

We move all terms to the left:

(4)-(2/5F+11)=0



Domain of the equation: 5F+11)!=0

F∈R



We get rid of parentheses

-2/5F-11+4=0

We multiply all the terms by the denominator


-11*5F+4*5F-2=0

Wy multiply elements

-55F+20F-2=0

We add all the numbers together, and all the variables

-35F-2=0

We move all terms containing F to the left, all other terms to the right

-35F=2

F=2/-35

F=-2/35

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