F(4)=3x+12

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Solution for F(4)=3x+12 equation:



(4)=3F+12
We move all terms to the left:
(4)-(3F+12)=0
We get rid of parentheses
-3F-12+4=0
We add all the numbers together, and all the variables
-3F-8=0
We move all terms containing F to the left, all other terms to the right
-3F=8
F=8/-3
F=-2+2/3

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