F(4)=3x+12

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Solution for F(4)=3x+12 equation: 



(4)=3F+12

We move all terms to the left:

(4)-(3F+12)=0

We get rid of parentheses

-3F-12+4=0

We add all the numbers together, and all the variables

-3F-8=0

We move all terms containing F to the left, all other terms to the right

-3F=8

F=8/-3

F=-2+2/3

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