F(6)=x2+10

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Solution for F(6)=x2+10 equation: 



(6)=F2+10

We move all terms to the left:

(6)-(F2+10)=0

We add all the numbers together, and all the variables

-(+F^2+10)+6=0

We get rid of parentheses

-F^2-10+6=0

We add all the numbers together, and all the variables

-1F^2-4=0

a = -1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-1)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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