F(X)=(2x2+160x)/x

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Solution for F(X)=(2x2+160x)/x equation:



(F)=(2F^2+160F)/F
We move all terms to the left:
(F)-((2F^2+160F)/F)=0
Domain of the equation: F)!=0
F!=0/1
F!=0
F∈R
We multiply all the terms by the denominator
F*F)-((2F^2+160F)=0
Wy multiply elements
F^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{2}=0$

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