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(F)=25F^2-10F+1
We move all terms to the left:
(F)-(25F^2-10F+1)=0
We get rid of parentheses
-25F^2+F+10F-1=0
We add all the numbers together, and all the variables
-25F^2+11F-1=0
a = -25; b = 11; c = -1;
Δ = b2-4ac
Δ = 112-4·(-25)·(-1)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{21}}{2*-25}=\frac{-11-\sqrt{21}}{-50} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{21}}{2*-25}=\frac{-11+\sqrt{21}}{-50} $
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