F(a+3)=3(a+3)+7

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Solution for F(a+3)=3(a+3)+7 equation: 



(F+3)=3(F+3)+7

We move all terms to the left:

(F+3)-(3(F+3)+7)=0

We get rid of parentheses

F-(3(F+3)+7)+3=0



We calculate terms in parentheses: -(3(F+3)+7), so:

3(F+3)+7

We multiply parentheses

3F+9+7

We add all the numbers together, and all the variables

3F+16

Back to the equation:

-(3F+16)



We get rid of parentheses

F-3F-16+3=0

We add all the numbers together, and all the variables

-2F-13=0

We move all terms containing F to the left, all other terms to the right

-2F=13

F=13/-2

F=-6+1/2

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