F(c)=9/5(35)+32

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Solution for F(c)=9/5(35)+32 equation: 



(F)=9/5(35)+32

We move all terms to the left:

(F)-(9/5(35)+32)=0

We get rid of parentheses

F-32-9/535=0

We multiply all the terms by the denominator


F*535-9-32*535=0

We add all the numbers together, and all the variables

F*535-17129=0

Wy multiply elements

535F-17129=0

We move all terms containing F to the left, all other terms to the right

535F=17129

F=17129/535

F=32+9/535

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