F(m)=4(m)2-2(m)+3

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Solution for F(m)=4(m)2-2(m)+3 equation: 



(F)=4(F)2-2(F)+3

We move all terms to the left:

(F)-(4(F)2-2(F)+3)=0

We add all the numbers together, and all the variables

-(+4F^2-2F+3)+F=0

We get rid of parentheses

-4F^2+2F+F-3=0

We add all the numbers together, and all the variables

-4F^2+3F-3=0

a = -4; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-4)·(-3)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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