F(m-3)=2(m-3)-5

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Solution for F(m-3)=2(m-3)-5 equation: 



(F-3)=2(F-3)-5

We move all terms to the left:

(F-3)-(2(F-3)-5)=0

We get rid of parentheses

F-(2(F-3)-5)-3=0



We calculate terms in parentheses: -(2(F-3)-5), so:

2(F-3)-5

We multiply parentheses

2F-6-5

We add all the numbers together, and all the variables

2F-11

Back to the equation:

-(2F-11)



We get rid of parentheses

F-2F+11-3=0

We add all the numbers together, and all the variables

-1F+8=0

We move all terms containing F to the left, all other terms to the right

-F=-8

F=-8/-1

F=+8

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