F(n)=(2n-2)+2

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Solution for F(n)=(2n-2)+2 equation: 



(F)=(2F-2)+2

We move all terms to the left:

(F)-((2F-2)+2)=0



We calculate terms in parentheses: -((2F-2)+2), so:

(2F-2)+2

We get rid of parentheses

2F-2+2

We add all the numbers together, and all the variables

2F

Back to the equation:

-(2F)



We add all the numbers together, and all the variables

-F=0

F=0/-1

F=0

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