F(n)=(2n-2)+2,52

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Solution for F(n)=(2n-2)+2,52 equation: 



(F)=(2F-2)+2.52

We move all terms to the left:

(F)-((2F-2)+2.52)=0



We calculate terms in parentheses: -((2F-2)+2.52), so:

(2F-2)+2.52

We get rid of parentheses

2F-2+2.52

We add all the numbers together, and all the variables

2F+0.52

Back to the equation:

-(2F+0.52)



We get rid of parentheses

F-2F-0.52=0

We add all the numbers together, and all the variables

-1F-0.52=0

We move all terms containing F to the left, all other terms to the right

-F=0.52

F=0.52/-1

F=-0.52/1

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