F(n)=2f(n-1)+6

Solution for F(n)=2f(n-1)+6 equation:

Simplifying
F(n) = 2f(n + -1) + 6

Multiply F * n
nF = 2f(n + -1) + 6

Reorder the terms:
nF = 2f(-1 + n) + 6
nF = (-1 * 2f + n * 2f) + 6
nF = (-2f + 2fn) + 6

Reorder the terms:
nF = 6 + -2f + 2fn

Solving
nF = 6 + -2f + 2fn

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2fn' to each side of the equation.
-2fn + nF = 6 + -2f + 2fn + -2fn

Combine like terms: 2fn + -2fn = 0
-2fn + nF = 6 + -2f + 0
-2fn + nF = 6 + -2f

Reorder the terms:
-6 + 2f + -2fn + nF = 6 + -2f + -6 + 2f

Reorder the terms:
-6 + 2f + -2fn + nF = 6 + -6 + -2f + 2f

Combine like terms: 6 + -6 = 0
-6 + 2f + -2fn + nF = 0 + -2f + 2f
-6 + 2f + -2fn + nF = -2f + 2f

Combine like terms: -2f + 2f = 0
-6 + 2f + -2fn + nF = 0

The solution to this equation could not be determined.