F(n)=3(n)/9

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Solution for F(n)=3(n)/9 equation: 



(F)=3(F)/9

We move all terms to the left:

(F)-(3(F)/9)=0

We add all the numbers together, and all the variables

F-(+3F/9)=0

We get rid of parentheses

F-3F/9=0

We multiply all the terms by the denominator


F*9-3F=0

We add all the numbers together, and all the variables

-3F+F*9=0

Wy multiply elements

-3F+9F=0

We add all the numbers together, and all the variables

6F=0

F=0/6

F=0

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