F(n)=3+4(5-1)

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Solution for F(n)=3+4(5-1) equation: 



(F)=3+4(5-1)

We move all terms to the left:

(F)-(3+4(5-1))=0

We add all the numbers together, and all the variables

F-(3+44)=0

We add all the numbers together, and all the variables

F-47=0

We move all terms containing F to the left, all other terms to the right

F=47

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