F(n)=4+10(n-1)

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Solution for F(n)=4+10(n-1) equation: 



(F)=4+10(F-1)

We move all terms to the left:

(F)-(4+10(F-1))=0



We calculate terms in parentheses: -(4+10(F-1)), so:

4+10(F-1)

determiningTheFunctionDomain
10(F-1)+4

We multiply parentheses

10F-10+4

We add all the numbers together, and all the variables

10F-6

Back to the equation:

-(10F-6)



We get rid of parentheses

F-10F+6=0

We add all the numbers together, and all the variables

-9F+6=0

We move all terms containing F to the left, all other terms to the right

-9F=-6

F=-6/-9

F=2/3

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