F(n)=6+2(n-1)

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Solution for F(n)=6+2(n-1) equation: 



(F)=6+2(F-1)

We move all terms to the left:

(F)-(6+2(F-1))=0



We calculate terms in parentheses: -(6+2(F-1)), so:

6+2(F-1)

determiningTheFunctionDomain
2(F-1)+6

We multiply parentheses

2F-2+6

We add all the numbers together, and all the variables

2F+4

Back to the equation:

-(2F+4)



We get rid of parentheses

F-2F-4=0

We add all the numbers together, and all the variables

-1F-4=0

We move all terms containing F to the left, all other terms to the right

-F=4

F=4/-1

F=-4

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