F(n)=F(F(n-1))+F(n-F(n-1))

Solution for F(n)=F(F(n-1))+F(n-F(n-1)) equation:

(F)=((F-1))+(F-(F-1))

We move all terms to the left:

(F)-(((F-1))+(F-(F-1)))=0


We calculate terms in parentheses: -(((F-1))+(F-(F-1))), so:

((F-1))+(F-(F-1))


We calculate terms in parentheses: +((F-1)), so:

(F-1)

We get rid of parentheses

F-1

Back to the equation:

+(F-1)



We calculate terms in parentheses: +(F-(F-1)), so:

F-(F-1)

We get rid of parentheses

F-F+1

We add all the numbers together, and all the variables

1

Back to the equation:

+(1)


We get rid of parentheses

F-1+1

We add all the numbers together, and all the variables

F

Back to the equation:

-(F)


We add all the numbers together, and all the variables

=0

F=0/1

F=0