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(F)=F2+2F+5
We move all terms to the left:
(F)-(F2+2F+5)=0
We add all the numbers together, and all the variables
-(+F^2+2F+5)+F=0
We get rid of parentheses
-F^2-2F+F-5=0
We add all the numbers together, and all the variables
-1F^2-1F-5=0
a = -1; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation
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