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(F)=(((5F+16))/(5))-16
We move all terms to the left:
(F)-((((5F+16))/(5))-16)=0
We multiply all the terms by the denominator
F*5)-16)-((((5F+16))=0
Wy multiply elements
5F^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$F=\frac{-b}{2a}=\frac{0}{10}=0$
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