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(F)=(-F-2)(-2F-3)
We move all terms to the left:
(F)-((-F-2)(-2F-3))=0
We add all the numbers together, and all the variables
F-((-1F-2)(-2F-3))=0
We multiply parentheses ..
-((+2F^2+3F+4F+6))+F=0
We calculate terms in parentheses: -((+2F^2+3F+4F+6)), so:We add all the numbers together, and all the variables
(+2F^2+3F+4F+6)
We get rid of parentheses
2F^2+3F+4F+6
We add all the numbers together, and all the variables
2F^2+7F+6
Back to the equation:
-(2F^2+7F+6)
F-(2F^2+7F+6)=0
We get rid of parentheses
-2F^2+F-7F-6=0
We add all the numbers together, and all the variables
-2F^2-6F-6=0
a = -2; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·(-2)·(-6)
Δ = -12
Delta is less than zero, so there is no solution for the equation
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