F(x)=(2/3x+9)-2

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Solution for F(x)=(2/3x+9)-2 equation: 



(F)=(2/3F+9)-2

We move all terms to the left:

(F)-((2/3F+9)-2)=0



Domain of the equation: 3F+9)-2)!=0

F∈R



We multiply all the terms by the denominator


F*3F+9)-2)-((2=0

We add all the numbers together, and all the variables

F*3F=0

Wy multiply elements

3F^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{6}=0$

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