F(x)=(3/10-5x)+1

Solution for F(x)=(3/10-5x)+1 equation:

(F)=(3/10-5F)+1

We move all terms to the left:

(F)-((3/10-5F)+1)=0


Domain of the equation: 10-5F)+1)!=0

We move all terms containing F to the left, all other terms to the right

-5F)+1)!=-10

F!=-10/1

F!=-10

F∈R


We add all the numbers together, and all the variables

F-((-5F+3/10)+1)=0

We multiply all the terms by the denominator


F*10)+1)-((-5F+3=0

We add all the numbers together, and all the variables

-5F+F*10)+1)-((+3=0

Wy multiply elements

10F^2-5F+3=0

a = 10; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·10·3
Δ = -95
Delta is less than zero, so there is no solution for the equation