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(F)=(3F+13)/2
We move all terms to the left:
(F)-((3F+13)/2)=0
We multiply all the terms by the denominator
F*2)-((3F+13)=0
Wy multiply elements
2F^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$F=\frac{-b}{2a}=\frac{0}{4}=0$
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