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(F)=(50-2F)(3+0.4F)
We move all terms to the left:
(F)-((50-2F)(3+0.4F))=0
We add all the numbers together, and all the variables
F-((-2F+50)(0.4F+3))=0
We multiply parentheses ..
-((+0F^2-6F+0F+150))+F=0
We calculate terms in parentheses: -((+0F^2-6F+0F+150)), so:We add all the numbers together, and all the variables
(+0F^2-6F+0F+150)
We get rid of parentheses
0F^2-6F+0F+150
We add all the numbers together, and all the variables
F^2-5F+150
Back to the equation:
-(F^2-5F+150)
F-(F^2-5F+150)=0
We get rid of parentheses
-F^2+F+5F-150=0
We add all the numbers together, and all the variables
-1F^2+6F-150=0
a = -1; b = 6; c = -150;
Δ = b2-4ac
Δ = 62-4·(-1)·(-150)
Δ = -564
Delta is less than zero, so there is no solution for the equation
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