F(x)=(50-2x)(3+0,4x)

Solution for F(x)=(50-2x)(3+0,4x) equation:

(F)=(50-2F)(3+0.4F)

We move all terms to the left:

(F)-((50-2F)(3+0.4F))=0

We add all the numbers together, and all the variables

F-((-2F+50)(0.4F+3))=0

We multiply parentheses ..

-((+0F^2-6F+0F+150))+F=0


We calculate terms in parentheses: -((+0F^2-6F+0F+150)), so:

(+0F^2-6F+0F+150)

We get rid of parentheses

0F^2-6F+0F+150

We add all the numbers together, and all the variables

F^2-5F+150

Back to the equation:

-(F^2-5F+150)


We add all the numbers together, and all the variables

F-(F^2-5F+150)=0

We get rid of parentheses

-F^2+F+5F-150=0

We add all the numbers together, and all the variables

-1F^2+6F-150=0

a = -1; b = 6; c = -150;
Δ = b2-4ac
Δ = 62-4·(-1)·(-150)
Δ = -564
Delta is less than zero, so there is no solution for the equation