F(x)=(9x-4)/5

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Solution for F(x)=(9x-4)/5 equation: 



(F)=(9F-4)/5

We move all terms to the left:

(F)-((9F-4)/5)=0

We multiply all the terms by the denominator


F*5)-((9F-4)=0

Wy multiply elements

5F^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{10}=0$

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