F(x)=(x+2)(x+6)

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Solution for F(x)=(x+2)(x+6) equation:



(F)=(F+2)(F+6)
We move all terms to the left:
(F)-((F+2)(F+6))=0
We multiply parentheses ..
-((+F^2+6F+2F+12))+F=0
We calculate terms in parentheses: -((+F^2+6F+2F+12)), so:
(+F^2+6F+2F+12)
We get rid of parentheses
F^2+6F+2F+12
We add all the numbers together, and all the variables
F^2+8F+12
Back to the equation:
-(F^2+8F+12)
We add all the numbers together, and all the variables
F-(F^2+8F+12)=0
We get rid of parentheses
-F^2+F-8F-12=0
We add all the numbers together, and all the variables
-1F^2-7F-12=0
a = -1; b = -7; c = -12;
Δ = b2-4ac
Δ = -72-4·(-1)·(-12)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*-1}=\frac{6}{-2} =-3 $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*-1}=\frac{8}{-2} =-4 $

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