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(F)=(F+5)(F+2)
We move all terms to the left:
(F)-((F+5)(F+2))=0
We multiply parentheses ..
-((+F^2+2F+5F+10))+F=0
We calculate terms in parentheses: -((+F^2+2F+5F+10)), so:We add all the numbers together, and all the variables
(+F^2+2F+5F+10)
We get rid of parentheses
F^2+2F+5F+10
We add all the numbers together, and all the variables
F^2+7F+10
Back to the equation:
-(F^2+7F+10)
F-(F^2+7F+10)=0
We get rid of parentheses
-F^2+F-7F-10=0
We add all the numbers together, and all the variables
-1F^2-6F-10=0
a = -1; b = -6; c = -10;
Δ = b2-4ac
Δ = -62-4·(-1)·(-10)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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