F(x)=(x-5)+(2x-45)

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Solution for F(x)=(x-5)+(2x-45) equation: 



(F)=(F-5)+(2F-45)

We move all terms to the left:

(F)-((F-5)+(2F-45))=0



We calculate terms in parentheses: -((F-5)+(2F-45)), so:

(F-5)+(2F-45)

We get rid of parentheses

F+2F-5-45

We add all the numbers together, and all the variables

3F-50

Back to the equation:

-(3F-50)



We get rid of parentheses

F-3F+50=0

We add all the numbers together, and all the variables

-2F+50=0

We move all terms containing F to the left, all other terms to the right

-2F=-50

F=-50/-2

F=+25

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