F(x)=(x3+2)2+3x-1(0,3)

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Solution for F(x)=(x3+2)2+3x-1(0,3) equation:



(F)=(F3+2)2+3F-1(0.3)
We move all terms to the left:
(F)-((F3+2)2+3F-1(0.3))=0
We add all the numbers together, and all the variables
-((+F^3+2)2+3F-1(0.3))+F=0
We calculate terms in parentheses: -((+F^3+2)2+3F-1(0.3)), so:
(+F^3+2)2+3F-1(0.3)
We do not support eFpression: F^3

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