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(F)=-2/3F+3
We move all terms to the left:
(F)-(-2/3F+3)=0
Domain of the equation: 3F+3)!=0We get rid of parentheses
F∈R
F+2/3F-3=0
We multiply all the terms by the denominator
F*3F-3*3F+2=0
Wy multiply elements
3F^2-9F+2=0
a = 3; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·3·2
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*3}=\frac{9-\sqrt{57}}{6} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*3}=\frac{9+\sqrt{57}}{6} $
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