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(F)=-2F^2+3F-11
We move all terms to the left:
(F)-(-2F^2+3F-11)=0
We get rid of parentheses
2F^2-3F+F+11=0
We add all the numbers together, and all the variables
2F^2-2F+11=0
a = 2; b = -2; c = +11;
Δ = b2-4ac
Δ = -22-4·2·11
Δ = -84
Delta is less than zero, so there is no solution for the equation
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