F(x)=-2x2-16x+35

Solution for F(x)=-2x2-16x+35 equation:

(F)=-2F^2-16F+35

We move all terms to the left:

(F)-(-2F^2-16F+35)=0

We get rid of parentheses

2F^2+16F+F-35=0

We add all the numbers together, and all the variables

2F^2+17F-35=0

a = 2; b = 17; c = -35;
Δ = b2-4ac
Δ = 172-4·2·(-35)
Δ = 569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{569}}{2*2}=\frac{-17-\sqrt{569}}{4}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{569}}{2*2}=\frac{-17+\sqrt{569}}{4}
$