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(F)=-3/5F-17
We move all terms to the left:
(F)-(-3/5F-17)=0
Domain of the equation: 5F-17)!=0We get rid of parentheses
F∈R
F+3/5F+17=0
We multiply all the terms by the denominator
F*5F+17*5F+3=0
Wy multiply elements
5F^2+85F+3=0
a = 5; b = 85; c = +3;
Δ = b2-4ac
Δ = 852-4·5·3
Δ = 7165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-\sqrt{7165}}{2*5}=\frac{-85-\sqrt{7165}}{10} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+\sqrt{7165}}{2*5}=\frac{-85+\sqrt{7165}}{10} $
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