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(F)=-4F(F+7)
We move all terms to the left:
(F)-(-4F(F+7))=0
We calculate terms in parentheses: -(-4F(F+7)), so:We get rid of parentheses
-4F(F+7)
We multiply parentheses
-4F^2-28F
Back to the equation:
-(-4F^2-28F)
4F^2+28F+F=0
We add all the numbers together, and all the variables
4F^2+29F=0
a = 4; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·4·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*4}=\frac{-58}{8} =-7+1/4 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*4}=\frac{0}{8} =0 $
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