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(F)=-5/2F+4=
We move all terms to the left:
(F)-(-5/2F+4)=0
Domain of the equation: 2F+4)!=0We get rid of parentheses
F∈R
F+5/2F-4=0
We multiply all the terms by the denominator
F*2F-4*2F+5=0
Wy multiply elements
2F^2-8F+5=0
a = 2; b = -8; c = +5;
Δ = b2-4ac
Δ = -82-4·2·5
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{6}}{2*2}=\frac{8-2\sqrt{6}}{4} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{6}}{2*2}=\frac{8+2\sqrt{6}}{4} $
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